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The radius of a sphere is increasing at a rate of 2 meters per second. At what rate is the volume increasing when the radius is equal to 4 meters?
This type of problem is known as a "related rate" problem. In this sort of problem, we know the rate of change of one variable (in this case, the radius) and need to find the rate of change of another variable (in this case, the volume), at a certain point in time (in this case, when r = 4 ). The reason why such a problem can be solved is that the variables themselves have a certain relation between them that can be used to find the relation between the known rate of change and the unknown rate of change.
Related rate problems can be solved through the following steps:
Step one: Separate "general" and "particular" information.
General information is information contained in the problem that is true at all times. Particular information is information that is true only at the particular instant that the problem is asking about.
For example, in this problem, the general information is that the radius is growing at a rate of 2 meters per second. Thus, if we let the radius of the sphere be represented by r , we can say that r'(t) =2 m/s.
The particular information is that at the moment of interest, r(t) = 4 .
It is important to separate out these two types of information because information about the particular case must be set aside and must not be used until the very last step of solving the problem. One mistake that students frequently make is to use the particular information too early. This invariably leads to incorrect answers.
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