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One of the uses of the definite integral is that it can help us find the average value of a function on an interval [a, b]. The formula for the average value on an interval [a, b] is as follows:
|favg = f (x)dx|
To see why this is the case, consider this form of the equation:
|favg(b - a) = f (x)dx|
The left side of the equation is the area of rectangle with base of (b - a) and height of favg. The right side of the equation is the area under the curve of f over the interval with length (b - a). These areas are depicted below:
The equation for the average value is a statement of the intuitive fact that if we construct a rectangle with the height favg and width (b - a), its area should be the same as the area under curve from a to b.
The mean value theorem for integrals states the following: if f is a continuous function on [a, b], there exists at least one c on [a, b] such that
|f (c) = f (x)dx|
In other words, the MVT for integrals states that every continuous function attains its average value at least once on an interval.
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