Problem : Compute sin^{2}(x)cos(x)dx .
Making the change of variables u = sin(x) , the integral becomes
u ^{2} du = + C |
Problem : Find 2xe ^{x2+1} dx .
Letting u = 1 + x ^{2} , we have
2xe ^{x2+1} dx = e ^{u} du = e ^{u}|_{1} ^{2} = e ^{2} - e. |
Problem : Compute dx .
Setting u = log(x) , we have
dx = du = log(u) + C = log(log(x)) + C |