Computing Integrals
Problems
Problem :
Compute
x sin(x)dx
.
x sin(x)dx
|
= | - x cos(x) - (- cos(x))dx
|
|
| = | - x cos(x) + sin(x) + C |
Problem :
Find
x
2
e
x
dx
.
x
2
e
x
dx
|
= |
x
2
e
x|0
1 = 2xe
x
dx
|
|
| = |
e - 2xe
x
dx
|
Applying integration by parts again, we get
2xe
x
dx
|
= | 2xe
x|0
1 - 2e
x
dx
|
|
| = | 2e - (2e x|0 1) | ||
| = | 2 |
Substituting the value of this integral back in the first computation yields
x
2
e
x
dx = e - 2
|
Problem :
Express
sinn+2(x)dx
in terms of
sinn(x)dx
by
integrating by parts twice.
sinn+2(x)dx
, the integral we are trying to compute.
Integrating by parts gives
sinn+2(x)dx
|
= |
sinn+1(x)sin(x)dx
|
|
| = | sinn+1(x)(- cos(x)) - (n + 1)sinn(x)cos(x)(- cos(x))dx
|
||
| = | -sinn+1(x)cos(x) + (n + 1) sinn(x)cos2(x)dx
|
Integrating this new integral by parts, we have
sinn(x)cos2(x)dx
|
= |
sinn(x)(1 - sin2(x))dx
|
|
= sinn(x)dx - sinn+2(x)dx
|
|||
= sinn(x)dx - I
|
Thus
I = - sinn+1(x)cos(x) + (n + 1)
sinn(x)dx - I
,
|
so
I = sinn+1(x)cos(x) +
sinn(x)dx
|
x sin(x)dx
x
2
e
x
dx
,
sinn+1(x)cos(x) +





