**Problem : **

Reproduce a drawing of a Carnot cycle.

See .

**Problem : **

On your Carnot cycle drawing, shade the region that represents the heat consumed by the system at the higher temperature.

Heat Consumed at *τ*_{h}

**Problem : **

On the same drawing, now shade in a distinct manner the region that represents the heat that is unable to be converted to work.

Heat Unusable by the Device

**Problem : **

Suppose we have a heat engine in which *σ*_{H} - *σ*_{L} = *N*_{0}, where
*N*_{0} is Avogadro's number. Suppose further that *T*_{l} = 300*K* and
*T*_{h} = 600*K*. Give the work done per cycle.

The work done is the product of the temperature difference and the
entropy difference, so *W* = 300*k*_{B}*N*_{0} = 2493 Joules.

**Problem : **

For an isothermal and isobaric process, what is the change in the Gibbs free energy?

We simply use the identity associated with the Gibbs free energy, and
letting *dτ* and *dp* be zero, we find: *dG* = *μ* *dN*.

Take a Study Break!