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Please Note:
The last administration of the old SAT was on 1/22/05. Beginning 3/12/05, only the New SAT will be administered. You should be studying the New SAT book. Go there!
Rates
Rates are a special kind of ratio that deal with related
quantities that have different units. The relationship between these
two different quantities is defined by a rate:
![]() That equation might seem a little complicated, but it
will seem much simpler once we give some concrete examples. The
most common rate questions on the SAT deal with speed, work, or
price, so we’ll use those.
Speed
In rate questions dealing with speed, you will usually
find the first quantity measured in time, the second measured in
distance, and the rate in distance covered per second, minute, or
hour, a unit known as speed. If you traveled for 7 hours
at 30 miles per hour, then:
![]() Notice how the units of “hour” canceled out, since the
hour in the rate is at the bottom of the fraction, while the unit
for the time is a normal number (meaning it could also be written
as 7
Work
In rate questions dealing with work, you will usually
find the first quantity measured in time, the second quantity measured
in work done, and the rate in measured in work done per time. If
you worked for 5 hours and dug 3 ditches
an hour, then:
![]() Notice how the “hour” units canceled out.
Price
In rate questions dealing with price, you will usually
find the first quantity measured in numbers of items, the second
measured in price, and the rate in price per item. Let’s say you
had 6 cucumbers, and you knew that cucumbers cost $.50 each.
![]() Notice how the units of “cucumber” canceled out.
Simple Rate Problems
Simple SAT rate problems might test your ability to solve
for any one of the three aspects of a rate equation: quantity 1,
quantity 2, or the rate. The key to solving any rate
problem is determining which values fit into which of the categories.
Once you’ve figured out which information the question is giving
you, all you have to do is plug in the numbers and work out the
equation.
Take a look at the following example of a simple rate
problem:
To answer this question let’s first define what we know:
First off, this problem contains a little trick. Did you
notice that the units of time in the rate and input are not the
same? The question states that the salesman sells .3 cars
per hour, while asking you to figure out how many
cars he will sell in 15 days. We included
this trick in this sample problem because it is one that the SAT
occasionally likes to play. So when you see rate questions dealing
with time, be careful.
Before beginning to solve the problem, you must equalize
the time units of hours and days. Since the salesman works 8 hours
a day:
![]() Now that the units are equalized, the problem can be answered
using the rate equation:
![]() so
![]() The salesmen sold 36 cars. Notice that in
this problem, the hours unit for quantity 1 cancels with
the
Complicated Rate Problems
Complicated SAT rate problems can involve more than one
rate. Such problems might ask you to compare in some way two different
objects moving at a different rate or to determine the distance
traveled by an object going at two different rates. There is no
way for us to cover every single example of a complicated rate problem
in this section. We will provide one good example here, but you
should also pay attention to these rate problems when you come upon
them in practice tests.
We know Griselda traveled at a rate of 3 km/hr
on the way to the store and 2 km/hr back from the store.
We also know it took her a total of 5 hours to make
the trip. Finally, since the distance between the store and Griselda’s
house remained constant for the trip there and back, we know that
she must have spent a different amount of time traveling to the store
and back. In fact, we know precisely the ratio between the time
she spent walking to the store and the time she spent walking back.
Since Griselda walked
![]() where y stands for the number
of hours Griselda spent walking home from the store. Now, to solve
the equation for y
![]() We now know Griselda spent 3 hours walking
home from the store. If we plug that 3 into the equation
for her walk home we get:
![]() You can check this answer by looking back at the original
question and making sure that the distance of 6 km
works out. We know Griselda was walking at the speed of 3 km/hr
to the store, and that the distance to the store was 6 km.
Therefore, it took her 2 hours to walk to the store.
We also know Griselda walked at the speed of 2 km/hr
back from the store. Since the distance was 6 kilometers,
it must have taken her 3 hours to walk back. In sum, then,
it took her 5 hours to walk to and from the store,
which fits the question perfectly.
Rate Problems with Variables
The SAT will occasionally ask rate problems using variables
rather than numbers. These questions can be difficult because the
variables can make it hard for you to figure out what refers to
quantity 1, quantity 2, and the rate,
and also because they can cause some confusion about what the question
is asking you to do.
Many test-prep books recommend that you try to answer
this question by substituting in numbers for the variables and then
working out all the answer choices to see which one works. This
method will work, but it’s slow and laborious, and if you have a
good understanding of rates, you would be better off just dealing
with the variables directly. We’ll cover both methods here.
Dealing Directly with the Variables
The key to answering this question is figuring out what
the question wants and then figuring out how to give it what it
wants. Looking at this question, we can see that the question is
asking for the total value of the soap produced in x hours.
Now, since we know that each bar of soap is worth 3 dollars,
you know that the total value of soap produced in x hours
is equal to:
![]() Now all you have to do is figure out how many bars of
soap are produced in x hours and multiply
that expression by 3. To figure out the expression
for soap produced in hours, you just need to identify what all those
variables mean. Since the rate equation is:
![]() we just have to figure out what variables go where. This
is pretty easy. The question explicitly says that the rate is “b bars
in h hours,” which means that the
rate is
![]() You already know that
so you just have to
substitute to get:![]() (D) is the right answer. Now, all that looks
like a lot of work, but please note that we explained every possible
step to teach you how to answer this question. If you were really good
at rates, you probably could have done many of those steps in your
head and just written this:
![]() and then substituted to get:
![]() See? Very quick.
Answering By Plugging In
If you aren’t so comfortable with rates, your best bet
is to substitute numbers in for the variables and then try to work
out the question. We’ll make b = 4, h = 2,
and x = 5.
So the question that once read:
now reads as:
With the variables gone, the question immediately becomes
much less difficult to comprehend. You can see that the rate is
![]() Then just multiply those 10 bars by the $3 charged
per bar, and you get $30. To find the answer, you need
to substitute the numbers into the answer choices and see which
works out to $30:
(D) is still the right answer. This method
is conceptually easier than the last, but you must do all the math
to use this method, which makes it take quite some time.
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