Uniform Circular Motion
Uniform circular motion occurs when a body
moves in a circular path with constant speed. For example, say you
swing a tethered ball overhead in a circle:
If we leave aside gravity for the moment, the only force
acting on the ball is the force of tension, T,
of the string. This force is always directed radially inward along
the string, toward your hand. In other words, the force acting on
a tetherball traveling in a circular path is always directed toward
the center of that circle.
Note that although the direction of the ball’s velocity
changes, the ball’s velocity is constant in magnitude and is always
tangent to the circle.
From kinematics, we know that acceleration is
the rate of change of the velocity vector with time. If we consider
two points very close together on the ball’s trajectory and calculate
, we find that the ball’s acceleration points
inward along the radius of the circle.
The acceleration of a body experiencing uniform circular
motion is always directed toward the center of the circle, so we
call that acceleration centripetal acceleration
a Latin word meaning “center-seeking.” We define the centripetal
acceleration of a body moving in a circle as:
where v is
the body’s velocity, and r is the
radius of the circle. The body’s centripetal acceleration is constant
in magnitude but changes in direction. Note that even though the
direction of the centripetal acceleration vector is changing, the
vector always points toward the center of the circle.
How This Knowledge Will Be Tested
Most of us are accustomed to think of “change” as a change
in magnitude, so it may be counterintuitive to think of the acceleration
vector as “changing” when its magnitude remains constant. You’ll
frequently find questions on SAT II Physics that will try to catch you
sleeping on the nature of centripetal acceleration. These questions
are generally qualitative, so if you bear in mind that the acceleration
vector is constant in magnitude, has a direction that always points
toward the center of the circle, and is always perpendicular to the
velocity vector, you should have no problem at all.
Wherever you find acceleration, you will also find force.
For a body to experience centripetal acceleration, a centripetal
force must be applied to it. The vector for this force is
similar to the acceleration vector: it is of constant magnitude,
and always points radially inward to the center of the circle, perpendicular
to the velocity vector.
We can use Newton’s Second Law and the equation for centripetal
acceleration to write an equation for the centripetal force that
maintains an object’s circular motion:
ball with a mass of 2 kg is swung in a circular path on a massless
rope of length 0.5 m. If the ball’s speed is 1 m/s, what is the
tension in the rope?
The tension in the rope is what provides the centripetal
force, so we just need to calculate the centripetal force using
the equation above:
Objects Released from Circular Motion
One concept that is tested frequently on SAT
II Physics is the trajectory of a circling body when the force providing
centripetal acceleration suddenly vanishes. For example, imagine swinging
a ball in a circle overhead and then letting it go. As soon as you
let go, there is no longer a centripetal force acting on the ball.
Recall Newton’s First Law: when no net force is acting on an object,
it will move with a constant velocity. When you let go of the ball,
it will travel in a straight line with the velocity it had when
you let go of it.
student is standing on a merry-go-round that is rotating counterclockwise,
as illustrated above. The student is given a ball and told to release
it in such a way that it knocks over the wicket at the top of the diagram.
At what point should the student release the ball?
When the student releases the ball, it will travel in
a straight line, tangent to the circle. In order to hit the wicket,
then, the student should release the ball at point B.