Problem 1.1:
| C2H5O- + CH3Br→C2H5OCH3 + Br- |
|
The above reaction has the following rate law:
| rate = k[C2H5O-]a[CH3Br]b |
|
If
[C2H5O-] is tripled while
[CH3Br]
is constant, the rate of the
reaction also triples. If
[CH3Br] is doubled while
[C2H5O-] is
constant, the rate of the reaction is also doubled. What are the values of a and b? What is the
overall reaction order?
Problem 1.2:
Which one of the following steps is rate-limiting?
Problem 1.3:
Sketch the reaction coordinate vs. energy for the reaction given in the previous problem.
