|C2H5O- + CH3Br→C2H5OCH3 + Br-|
|rate = k[C2H5O-]a[CH3Br]b|
There is a one to one ratio of proportionality for both reactants. The values of a and b are both one. The overall reaction order is the sum of a and b, two.
Problem : Which one of the following steps is rate-limiting?
Problem : Sketch the reaction coordinate vs. energy for the reaction given in the previous problem.
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