Problem : If the percent yield of the following equation is 55%, how many moles of H_{2}SO_{4} are produced when 44.8 L of SO_{3} are combined with excess water?
SO_{3}(g) + H_{2}O(l)→H_{2}SO_{4}(aq) |
= 2 moles SO_{3}(g) |
= 2 moles H_{2}SO_{4}(aq) |
55% = 0.55 = Actual Yield/(2 moles H_{2}SO_{4}(aq)) | |||
2 moles H_{2}SO_{4}(aq)×0.55 = 1.1 moles H_{2}SO_{4}(aq) |