**Problem : **
What dimensions do you need to know to determine the value of `arr[3][5][7]`
using only pointer arithmetic and the dereference operator (*)?

**Problem : **
Assuming that the second dimension were `SECOND` and the third
dimension were `THIRD`, calculate the value of `arr[3][5][7]` from the
pointer `arr` using pointer arithmetic and the dereference operator.

In general you multiply each index by the size of the greater dimensions. So the first index, 3, is multiplied by the second and third dimensions and the second index, 5, is multiplied by the third dimension.*(arr + 3 * SECOND * THIRD + 5 * THIRD + 7)

**Problem : **
As an exercise, write some code that will print out all of the integers
in the integer array without ever using the square brackets to index
into it. There are `n` integers in the array `arr`.

int i; for(i = 0; i < n; i++) { printf("%i\n", *(arr + i); }