Inequalities

Graphing Inequalities on a Number Line

Graphing Inequalities on a Number Line

Recall that a number line is a horizontal line that has points which correspond to numbers. The points are spaced according to the value of the number they correspond to; in a number line containing only whole numbers or integers, the points are equally spaced.

We can graph real numbers by representing them as points on the number line. For example, we can graph " 2 " on the number line:

We can also graph inequalities on the number line. The following graph represents the inequality x≤2 . The dark line represents all the numbers that satisfy x≤2 . If we pick any number on the dark line and plug it in for x , the inequality will be true.

The following graph represents the inequality x < 2 . Note that the open circle on 2 shows that 2 is not a solution to x < 2 .

Here are the graphs of x > 2 and x≥2 , respectively:

An inequality with a " ≠ " sign has a solution set which is all the real numbers except a single point (or a number of single points). Thus, to graph an inequality with a " ≠ " sign, graph the entire line with one point removed. For example, the graph of x≠2 looks like:

Using the Number Line to Solve Inequalities

We can use the number line to solve inequalities containing < , ≤ , > , and ≥ . To solve an inequality using the number line, change the inequality sign to an equal sign, and solve the equation. Then graph the point on the number line (graph it as an open circle if the original inequality was "<" or ">"). The number line should now be divided into 2 regions -- one to the left of the point and one to the right of the point

Next, pick a point in each region and "test" it -- see if it satisfies the inequality when plugged in for the variable. If it satisfies the inequality, draw a dark line from the point into that region, with an arrow at the end. This is the solution set to the equation: if one point in the region satisfies the inequality, the entire region will satisfy the inequality.

Example: -3(x - 2)≤12

Solve -3(x - 2) = 12 :

x - 2 = - 4
x = - 2

Graph x = - 2 , using a filled circle because the original inequality was ≤ :
Plug values into the equation -3(x - 2)≤12 :

Pick a point on the left of -2 ( -3 , for example):
-3(- 3 - 2)≤12 ?
15≤12 ? No.
Pick a point on the right of -2 ( 0 , for example):
-3(0 - 2)≤12 ?
6≤12 ? Yes.

Draw a dark line from -2 extending to the right, with an arrow at the end:

Thus, x≥ - 2 .