No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
Mastery Quizzes
Infographics
Graphic Novels
AP® Test Prep PLUS
AP® Practice & Lessons
My PLUS Activity
Note-taking
Bookmarking
Dashboard
Annual
$22.49/month + tax
Save
25%
on 2-49 accounts
Annual
$20.99/month + tax
Save
30%
on 50-99 accounts
Focused-studying
Ad-free experience
Study Guides for 1,000+ titles
Full Text content for 250+ titles
PLUS Study Tools
No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
Mastery Quizzes
Infographics
Graphic Novels
AP® Test Prep PLUS
AP® Practice & Lessons
My PLUS Activity
Note-taking
Bookmarking
Dashboard
Testimonials from SparkNotes
Customers
No Fear
provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays.
It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I
tutor high school students in a variety of subjects. Having access to the literature
translations helps me to stay informed about the various assignments. Your summaries and
translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with
understanding the crux of the text.
Kay
H.
Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
Create Account
Select Plan
3
Payment Info
4
Start 7-Day Free Trial!
Payment Information
You will only be charged after the completion of the 7-day free trial.
If you cancel your account before the free trial is over, you will not be charged.
You will only be charged after the completion of the 7-day free trial. If you cancel your account before the free trial is over, you will not be charged.
Order Summary
Annual
7-day Free Trial
SparkNotes PLUS
$29.99 / year
Annual
Quantity
51
PLUS Group Discount
$29.99 $29.99 / seat
Tax
$0.00
SPARK25
-$1.25
25% Off
Total billed on Nov 7, 2024 after 7-day free trail
$29.99
Total billed
$0.00
Due Today
$0.00
Promo code
This is not a valid promo code
Card Details
By placing your order you agree to our terms of service and privacy policy.
By saving your payment information you allow SparkNotes to charge you for future payments in accordance with their terms.
Powered by stripe
Legal
Google pay.......
Welcome to
Thank You!
Your group members can use the joining link below to redeem their membership. They will be prompted to log into an existing account or to create a new account.
All members under 16 will be required to obtain a parent's consent sent via link in an email.
Your Child’s Free Trial Starts Now!
Thank you for completing the sign-up process. Your child’s SparkNotes PLUS login credentials are [email] and the associated password.
If you have any questions, please visit our help center.
Your Free Trial Starts Now!
Please wait while we process your payment
Parent’s Email is Required
A parent must help manage your account. Enter their email below and we’ll send them a link to finish signing
up for SparkNotes PLUS.
We’ve sent an email to parentsname@email.com. In
order to access SparkNotes PLUS, your parent must click the link provided in the email.
We’ve sent an email to parentsname@email.com. In order to access
SparkNotes PLUS, your parent must follow the link provided in the email to complete the sign-up process.
Suppose an ice skater named Lindsay is gliding around on a frozen coordinate plane.
Define functions x(t), y(t), so that at time t (in seconds) Lindsay's position on the
coordinate plane is given by (x(t), y(t)). If Lindsay starts at time t = 0 and stops at
time t = 15, she will trace out the parametric curve consisting of the points (x(t), y(t))
with t in the interval [0, 15], perhaps like the one sketched below.
Figure %: Lindsay's Position, (x(t), y(t)), in the Coordinate Plane
Two questions naturally arise. First, what is Lindsay's velocity (direction and speed) at
any given moment? Second, how is it changing (that is, what is her acceleration)? It is
actually fairly easy to answer these questions using the derivative.
Lindsay's velocity at time t can be represented by an arrow with a certain direction and
length, called the velocity vector. The direction of the vector will indicate her
instantaneous direction, and the length of the vector will equal her instantaneous speed.
We would expect the direction of the velocity vector at time t to be the same as the
direction of the tangent line at (x(t), y(t)) to the curve describing Lindsay's path. If
we imagine the velocity vector to have its tail at the origin of a coordinate plane (rather
than at a point of tangency to the parametric curve), we need only specify the coordinates
of its head to give its length and direction.
It is fairly easy to see that the correct coordinates for the head of the velocity vector at
time t0 are simply
(x'(t0), y'(t0))
where the derivatives are with respect to t. The speed is equal to the length of this
velocity vector:
This is all illustrated in the figure below.
Figure %: The Velocity Vector for Lindsay
Note that the head of the velocity vector (with tail fixed at the origin), located at
(x'(t), y'(t)) at time t, traces out another parametric curve. The velocity vector of
this new curve at time t0,
(x''(t0), y''(t0))
is called the acceleration vector of the original curve at time t0. Its direction
indicates the instantaneous direction of motion of the head of the velocity vector and its
length is the speed at which the head of the velocity vector is moving.
It is important to realize that there is a difference between the length of the
acceleration vector, which is the rate at which the velocity it changing, and the rate at
which the speed is changing. For instance, if an object is moving in the circular path
(x(t), y(t)) = (cos(t), sin(t)), then the speed is constant (for (x'(t), y'(t)) = (- sin(t), cos(t)) has length = 1, yet the acceleration is
nonzero and has constant length -- (x''(t), y''(t)) = (- cos(t), - sin(t)) has length
= 1. One can think of this phenomenon as follows: the
acceleration contains contributions from the rate of change of the speed, and from the rate
of change of the direction of the velocity.