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No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
Mastery Quizzes
Infographics
Graphic Novels
AP® Test Prep PLUS
AP® Practice & Lessons
My PLUS Activity
Note-taking
Bookmarking
Dashboard
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Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with
understanding the crux of the text.
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Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
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Similarity is much like congruence, except in order for
polygons to be
similar, they only need to have the same shape. As we did with congruence, we
will study similarity in triangles to simplify things. Formally speaking, two
triangles are similar when their corresponding angles are equal and their
corresponding sides are proportional. For example, if triangles ABC and DEF are
similar, then angle pairs AB and DE, BC and EF, and CA and FE are all equal.
Also, AB/DE=BC/EF=CA/FD. If these three ratios are equal, then the
corresponding sides are said to be proportional.
Figure %: Triangles ABC, DEF, and HIJ are similar
An easy to way to create similar triangles is by drawing a line through a
triangle such that it intersects with two sides and is parallel to the third
side. This new line will form a new triangle that is smaller that the original,
but similar to it.
Figure %: Similar triangles
The line l, parallel to AC, creates the triangle DEB, which is similar to
triangle ACB. Another thing about the above diagram: because the two triangles
ACB and DEB are similar, DB/AB = EB/CB. We also know that AD/DB = CE/EB. This last relationship is just another application of similarity in triangles. In the next lesson we'll see how to prove triangles are simi
lar.