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No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
Mastery Quizzes
Infographics
Graphic Novels
AP® Test Prep PLUS
AP® Practice & Lessons
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Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with
understanding the crux of the text.
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Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
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While there is no simple formula to determine area for most
quadrilaterals, and most
polygons for that matter, we saw last
section that for the special quadrilaterals
parallelograms and
trapezoids there are specific formulas for
determining area. The area of a triangle,
however, does. This is why it is so important that any polygon can be divided
into a number of triangles. The area of a polygon is equal to the sum of the
areas of all of the triangles within it.
The area of a triangle can be calculated in three ways. The most common
expression for the area of a triangle is one-half the product of the base
and the height (1/2AH). The height is formally called the altitude, and is
equal to the length of the line segment with
one endpoint at a vertex and the other endpoint on
the line that contains the
side opposite the vertex. Like all altitudes, this
segment must be perpendicular to the line
containing the side. The side opposite a given vertex is called the base of a
triangle. Here are some triangles pictured with their altitudes.
Figure %: Various triangles and their altitudes
Another way to calculate the area of a triangle is called Heron's Formula, named
after the mathematician who first proved the formula worked. It is useful only
if you know the lengths of the sides of a triangle. The formula makes use of
the term semiperimeter. The semiperemeter of a triangle is equal to half
the sum of the lengths of the sides. Heron's Formula states that the area of a
triangle is equal to the square root of s(s-a)(s-b)(s-c), where s is the
semiperimeter of the triangle, and a, b, and c are the lengths of the three
sides. The proof of Heron's Formula is rather complex, and won't be discussed
here, but his formula works like a charm, especially if all that is known about
a triangle is the lengths of its sides.
The third and final way to calculate the area of a triangle has to do with the
angles as well as the side lengths of the
triangle. Any triangle has three sides and three angles. These are known as
the six parts of a triangle. Let the lengths of the sides of the triangle equal
a, b, and c. If the vertices opposite each length are angles of measure A, B,
and C, respectively, then the triangle would look like this:
Figure %: A triangle with side lengths a, b, and c and angle measures A, B, and
C
The area of such a triangle is equal to one-half the product of the length of
two of the sides and the sine of their included angle. So in the triangle
above, Area=1/2(ab sin(C)), or Area=1/2(bc sin(A)), or Area=1/2(ac sin(B)).
The sine of an angle is a trigonometric property that you can learn more about
in the Trigonometry SparkNote.
With these formulas, it is possible to calculate the area of a triangle any time
you have any of the following information: 1) the length of the base and its
altitude; 2) the lengths of all three sides; or 3) the length of two sides and
the measure of their included angle. With these tools, it is possible to
calculate the area of triangles, and, as we shall see, by summing the areas of
triangles within a polygon, it is possible to calculate the area of any polygon.