Problem :
A block of 10N rests on a plane inclined 45^{ o } . In addition a horizontal force of 10N is applied to the block. What is the normal force applied by the inclined plane?
We solve the problem by drawing a free body diagram, and resolving all force vectors into components parallel and perpendicular to the plane:
F _{Gâä¥} = F _{G}sin 45^{ o } = 10 sin 45^{ o } = 7.07N |
F _{âä¥} = F sin 45^{ o } = 10 sin 45^{ o } = 7.07N |