A block of 10N rests on a plane inclined 45 o . In addition a horizontal force of 10N is applied to the block. What is the normal force applied by the inclined plane?
We solve the problem by drawing a free body diagram, and resolving all force vectors into components parallel and perpendicular to the plane:
|F Gâä¥ = F Gsin 45 o = 10 sin 45 o = 7.07N|
|F âä¥ = F sin 45 o = 10 sin 45 o = 7.07N|