We solve the problem by drawing a free body diagram:

Now we find the sum of the x and y components of all three forces:

And sum these two vectors. The magnitude of the resultant force is given by:

And the direction is given by: θ = tan^-1(31.2/41.2) = 37.1 ^o , North of East. Thus the object experiences a force of 51.7 Newtons, directed 37.1 ^o North of East. Now we must find its acceleration, using Newton's Second Law:

To find the final velocity and position of the object, we simply use the equations learned in kinematics:

Thus, after 10 seconds, the object is moving with a velocity of 51.7 m/s, directed 31.7 degrees North of East. Also, the object has moved 258.5 meters, in the same direction.