Calculus Based Section: Rotational Inertia of Solid Bodies
In our study of rotational dynamics we skipped over exactly how to calculate the rotational inertia of a solid body. The process for calculating this quantity is quite complicated, and requires quite a bit of calculus. Thus we devote a section to calculating this quantity.
Consider a small section of a rod, a radius r from the axis of rotation, and with a mass δm , as shown below:
To get an exact answer for the moment of inertia, we take the limit as the δm gets smaller; as the rod is broken up into more and more pieces. Thus:
|I||=||r k 2 δm k|
|=||r 2 dm|
This integral equation is the basic equation for the moment of inertia of a solid body.
Even with this equation, it is quite difficult to calculate the moment of inertia of a solid body. We will go through an example to show how it is done. Let us simply return to the example of the solid rod of length L, and mass M, rotated about its center, as shown below.
However, we can also express ρ in terms of measured quantities: ρ = M/V = M/AL . Thus we can plug all this into our integral equation:
|I||=||r 2 dm|
|=||x 2( Adx)|
|=||x 2 dx|
Thus we now have an integral we can evaluate. We simply need to determine the limits. If we denote the axis of rotation to be at x = 0 , then we simply integrate from -L/2 to L/2:
|I||=||x 2 dx|
This is the equation for the moment of inertia of a thin rod, and it agrees with measured values.
In general, the moment of inertia of a solid body varies with MR 2 , where R is the measure of the radius, or length of a given object. To find the exact value of the moment of inertia, however, the complicated calculus is required.