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No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
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Problems 1
Problem :
Suppose that we have a fuel cell battery, in which electrons flow from a terminal in one half cell to a terminal in another. Explain this phenomenon in terms of the chemical potential.
We can look at the battery as two systems in diffusive contact through the connecting wire. The electrons simply then flow from the cell with the higher chemical potential to that with the lower until an equilibrium is reached, if ever.
Problem :
Show that the units of pressure as we have defined it agree with those of the conventional understanding of pressure.
The conventional units are
. We have defined
pressure so that we have an energy in the numerator and a volume in the
denominator. But remember that energy has the same units as work,
namely FORCE×LENGTH, and therefore we have
=
.
Problem :
Forcing a system into a small volume makes the energy of the system grow, whereas expanding the system, colloquially speaking, gives the particles more room to relax, and the energy of the system decreases (all for a process at constant entropy). Using the definition of pressure we've investigated, show what happens to the pressure at large volumes and very small volumes of the system. Does this agree with your intuition?
For a system of small volume for the number of particles, the energy is high. Increasing the volume some small amount, δV, will cause a great decrease in the energy U. Therefore, the pressure is:
)σ = -
= big positive
For a system of great volume for the number of particles, the energy is already low. Increasing the volume some small amount, δV, will only cause a small decrease in the energy U. Therefore, the pressure is:
)σ = -
= small positive
This makes sense to us. We expect a cramped system to have a high pressure and sprawling system to have low pressure.
Problem :
Is the energy of the system U an intensive or extensive variable?
Doubling the system should double the energy, so U is an extensive variable.
Problem :
Explain why the entropy is an extensive variable.
Remember that entropy was defined as σ = log g where g was the multiplicity function. We defined the entropy in this manner so that the entropies of two systems in contact would add together, since their individual g functions multiply together. So, doubling the system means that σnew = σoriginal + σduplicate = 2σoriginal. Therefore entropy is an extensive variable.
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