Problem : Blaise decides to build a barometer. He can't find any mercury in his workshop and decides to use water instead. Assume that the density of water is 1.00×10^{3} kg/m^{3} . If the atmospheric pressure is 7.60×10^{2} torr, how tall must his barometer be in order to obtain an accurate reading?
First, convert the atmospheric pressure to Pascals. 7.60×10^{2} torr = 101, 325 Pa . Now that all the variables are in SI units, rearrange P = ghρ to P/(gρ) = h and plug the variables into the equation.
= = 10.3 m |
Problem :
In a fit of inspiration and hot air, you have blown the world's largest balloon. Your two cousins, Bongo the 300 lb. gorilla and Jeeves the 70 lb. weakling, both want to climb to the top of your balloon. When Bongo goes, he goes in style. He wants to lay down on his 1 m by 5 m air bed at the summit. Jeeves proposes to bounce on the top of the balloon on his pogo stick, whose head has an area of 0.001 m^{2} . Assume that the masses of the bed and pogo stick are negligible, and that their occupants' weights are evenly distributed upon them.
You know that your balloon can sustain 200 more kPa of pressure on its surface before it pops. Assuming both can make it to the top without damaging the balloon (or themselves), which cousin(s) should you allow to climb?
P = F/A , so the first thing we need to do is convert everything to the appropriate units. Let's use SI units. 1 lb = 0.454 kg, and F = (mass)×(9.8 m/s^{2}) , so Bongo and Jeeves exert forces of 1330 and 311 Newtons, respectively. P = F/A , so Bongo has a pressure of P _{Bongo} = = 270 Pa. Jeeves exerts a pressure of P _{Jeeves} = (311 N)×(0.001 m^{2}) = 310 kPa. You should allow Bongo on, but not Jeeves.Problem : After an interdimensional mishap, Blaise finds himself on a strange planet with nothing but an empty barometer and a jar of alien liquid. After working with barometers for many years, Blaise has developed a keen sense of pressure. He reckons that the atmospheric pressure is 1.4 atmospheres. The label on the jar claims that the density of the liquid is 1.0×10^{5} . He pours the liquid into his barometer, and finds that the atmosphere supports a column 0.072 m tall. What is the gravitational acceleration g on this planet?
We can rearrange the barometer equation to solve for g :
= g |