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No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
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Graphic Novels
AP® Test Prep PLUS
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Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
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Approximate the area between the curve of y = x2 and the x - axis from x = 0 to
x = 1:
Figure %: Area bounded by a curve
The method to be used in this section to solve this problem is Riemann sums, which
involves subdividing the region into rectangles of equal width and adding up the areas of
all of the rectangles to approximate the area of the region.
Let's first use three subdivisions to approximate this area:
Figure %: Three subdivision of the region
Each of the regions has a width of 1/3 the interval from x = 0 to x = 1 which is 1/3. These will form the bases of the
rectangles, but what should be chosen for the height? One possibility would be to use the value of the function at the left
endpoint of each subdivision as the height. This is called a left-hand approximation.
Figure %: Left-hand approximation of area using three subdivisions
The left-hand approximation for the area is as follows:
(0) + + =
Another possibility is to use the value of the function at the right endpoint of each
subdivision as the height. This is called a right-hand approximation.
Figure %: Right-hand approximation of area using three subdivisions
The right-hand approximation for the area is as follows:
+ + (1) =
Finally, a third possibility is to use the value of the function at the midpoint of each of the
subdivisions as the height. This is called a midpoint approximation.
Figure %: Right-hand approximation of area using three subdivisions
The midpoint approximation for the area is as follows:
() + () + () =
Each of these three methods seems reasonable, yet each generated a different result for
the area. It seems as though no matter which point we choose for the height of the box,
we will never get the exact area, since there is always a margin of error present.
However, it also seems intuitive that if 10 subdivisions or 100 subdivisions were used
instead of only three, the error would decrease. This is indeed true. As the number of
subdivisions increases, the accuracy of the approximation goes up regardless of what
endpoint is being used as the height of the rectangles. This is a very important
observation, but discussing it further requires the establishment of some notation first:
Let's generalize the procedure of doing left-hand approximations to find the area under
the graph of f on the closed interval [a, b] using n subdivisions. With equal subdivisions, each rectangle has a width
of Δx = .
If we let x0 = a and xn = b, then x1 = x0 + Δx, x2 = x0 +2Δx, etc:
Figure %: Generalized subdivision method
Each of the subdivisions uses the left endpoint for the height, so the height of the first
subdivision is f (x0), the height of the second subdivision is f (x1), etc. Thus,
Ln, the "nth left-hand approximation" is equal to
Ln = f (x0)Δx + f (x1)Δx + ...f (xn-1)Δx
Defining xk as x0 + kΔx allows us to collapse the left-hand approximation
into:
Ln = f (xk)Δx
Similarly, the right-hand approximation could be written as
Rn = f (xk)Δx
Notice how this formula is just slightly different from the one for the left-hand
approximation. It was conjectured previously that using more subdivisions would improve the accuracy
of the approximations. To make this approximation exact, one would need an infinite
number of subdivisions, and limits allow us to get close to this: if A is the exact area of a region bound by a function
f, the x-axis, and the lines x = a and x = b, then