Calculus BC: Applications of the Derivative

Problem : Suppose Andrea decides to open a lemonade stand and her grandfather agrees to buy her all the supplies she needs. Now she has to decide what price she will charge for the lemonade. The more she charges per cup, the fewer cups people will buy. Andrea (who happens to be a mathematician) figures that the number of cups she will sell if she charges x cents per cup is approximately given by the function

Solution for Problem 1 >>

Andrea's total profit is the number of cups sold times the number of cents received for each cup. This profit is given by the function

p(x) = 1000xe -x/5

with derivative

p'(x)	=	1000 xe -x/5 + e -x/5
	=	1 - 1000e -x/5

Solving p'(x) = 0 for x , we get x = 5 , so Andrea should charge 5 cents per cup. She would then sell 1000/e 368 cups of lemonade, making $18.40 in profit.

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Problem : Find the minimum value of f (x) = - 2x ³ +3x ² + 12x - 1 in the interval [1, 4] .

Problem : Does the function g(x) = 3 - 2x attain a minimum value on the interval (1, 3) ?

Solution for Problem 3 >>

The fact that the boundary points are not included in the interval is crucial here. If x = 3 was included in the interval, g would attain a minimum on the interval of -3 at x = 3 . As is, g does not attain a minimum on the interval, because given any x in (1, 3) , we always have

g < g(x)

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