Problem : Suppose Andrea decides to open a lemonade stand and her grandfather agrees to buy her all the supplies she needs. Now she has to decide what price she will charge for the lemonade. The more she charges per cup, the fewer cups people will buy. Andrea (who happens to be a mathematician) figures that the number of cups she will sell if she charges x cents per cup is approximately given by the function
c(x) = 1000e ^{-x/5} |
p(x) = 1000xe ^{-x/5} |
p'(x) | = | 1000 xe ^{-x/5} + e ^{-x/5} | |
= | 1 - 1000e ^{-x/5} |
Problem : Find the minimum value of f (x) = - 2x ^{3} +3x ^{2} + 12x - 1 in the interval [1, 4] .
We first look for critical points.
f'(x) = - 6x ^{2} + 6x + 12 = - 6(x + 1)(x - 2) |
f (1) | = | 12 | |
f (2) | = | 19 | |
f (4) | = | -31 |
Problem : Does the function g(x) = 3 - 2x attain a minimum value on the interval (1, 3) ?
The fact that the boundary points are not included in the interval is crucial here. If x = 3 was included in the interval, g would attain a minimum on the interval of -3 at x = 3 . As is, g does not attain a minimum on the interval, because given any x in (1, 3) , we always have
g < g(x) |
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