Suppose Andrea decides to open a lemonade stand and her grandfather agrees to buy her
all the supplies she needs. Now she has to decide what price she will charge for the
lemonade. The more she charges per cup, the fewer cups people will buy.
Andrea (who happens to be a mathematician) figures that the number of cups she will sell
if she charges x cents per cup is approximately given by the function
What should Andrea charge to maximize her profits? How much will she make?
Andrea's total profit is the number of cups sold times the number of cents received for
each cup. This profit is given by the function
|p'(x)||=||1000xe-x/5 + e-x/5||
| ||=||1 - 1000e-x/5||
Solving p'(x) = 0
, we get x = 5
, so Andrea should charge 5
cents per cup.
She would then sell 1000/e 368
cups of lemonade, making $18.40 in profit.
Find the minimum value of f (x) = - 2x3 +3x2 + 12x - 1 in the interval [1, 4].
We first look for critical points.
|f'(x) = - 6x2 + 6x + 12 = - 6(x + 1)(x - 2)||
has only one critical point in the interval [1, 4]
, at x = 2
. Evaluating f
the critical point and the boundary points, we find
clearly takes on a minimum value on the interval [1, 4]
at x = 4
Does the function g(x) = 3 - 2x attain a minimum value on the interval (1, 3)?
The fact that the boundary points are not included in the interval is crucial here. If x = 3
was included in the interval, g
would attain a minimum on the interval of -3
x = 3
. As is, g
does not attain a minimum on the interval, because given any x
, we always have