SparkNotes: Free Study Guides No Fear Shakespeare: The Bard made easy SparkCharts: Just the facts TestPrep: SAT, ACT, and more 101s: College texts condensed Subject Finder: Browse by subject SparkCollege: Get in! SparkLife: 100% study-free home_bottom home_top BN_link
 
◄ PREVIOUS
Terms
NEXT ►
Problems
 

Applications of the Integral

 
 

Areas in the Plane

 
Recall that the area below the graph of the function f (x) from a to b is the definite integral
 

f (x)dx    

where area counts as negative when f (x) < 0. If the function f (x) takes on both positive and negative values in the interval [a, b], and we want to compute the total area counting all areas as positive, we need to refine our method. The correct thing to do is to break the integral up into several integrals corresponding to the parts of the interval on which the function is positive and those on which it is negative.
 
For example, let us calculate the area between the graph of f (x) = sin(x) and the x-axis from 0 to 2Π. If we were simply to compute the integral
 

sin(x)dx    

we would obtain 0, because the areas above and below the x-axis exactly cancel each other out weighted with opposite signs. Instead, we must take the integral of the absolute value of f, splitting it into two separate integrals in order to evaluate it:
 


| sin(x)| dx = | sin(x)| dx + | sin(x)| dx  
  = sin(x)dx + - sin(x)dx  
  = -cos(x)|0Π + cos(x)|Π2Π  
  = (1 + 1) + (1 + 1)  
  = 4  

Alternately, we could have noted from the symmetry of the graph of sin(x) that it is enough to calculate the area below the graph from 0 to Π and double it.
 
Integrals also enable us to calculate the area between the graphs of two functions (up to this point, the second function has always been f (x) = 0, with graph equal to the x- axis). For this, we note that the area between the graphs of two functions f and g is the difference of the area between the graph of f and the x-axis and the area between the graph of g and the x-axis. Hence the area between the graphs of f and g from a to b is given by:
 

f (x)dx - g(x)dx = f (x) - g(x)dx    

where the area is counted as positive when f (x) > g(x) and as negative when f (x) < g(x).
 
 
Help | Feedback | Make a request | Report an error | Send to a friend

◄ PREVIOUS
Terms
NEXT ►
Problems
 
 
 
 
 
 
Message Boards
Ask a question or start a discussion on the community boards.
  • Advanced Math
  • Beginner Math
  • Calculus
  • Chaos and Fractals
  • High School Math
  • Intriguing Problems
  • Number Theory
  • Precalculus
  •  
     
     
     
    Read on Your iPod
    Download the text version of this SparkNote to view on your iPod.
     
     
     
    SparkCharts
    A textbook's worth of information on an easy-to-read chart.
  • Math Basics
  • Calculus I
  • Calculus II
  • Calculus I
  • Calculus Reference
  •  
     
     
    Contact Us | Privacy Policy | Terms and Conditions | About | Sitemap
    ©2008 SparkNotes LLC, All Rights Reserved.