The most simple case of a collision is a one-dimensional, or head-on 
collision.  Because of the conservation of energy and momentum we are able to 
predict a great deal about these collisions, and to calculate relevant 
quantities after the collision occurs.  Before we do so, however, we must define 
exactly what is meant by a collision.
 
What is a Collision?
We all know, somewhat intuitively, the common meaning of a collision: two things 
hitting each other.  Whether the objects are two billiard balls, two particles, 
or two cars, this common definition applies.  The definition used in physics, 
however, is something more precise.  In physics, a collision has two aspects: 
-  Two particles hit each other 
-  A large force is felt by each particle for a relatively short amount of 
time.  
In this way, a collision can be seen as an event that imparts a large amount of 
impulse to the
objects involved.  In 
addtion, recall that impulse changes momentum.
A typical collision problem involves two particles with known initial velocities 
colliding; we are required to calculate the final velocity of each object.  If 
we knew the forces acting during the collision this would be easy.  Usually, 
however, we do not, and are forced to look for other methods of solving the 
problem.  For instance, two balls of the same masses and initial velocities upon 
hitting a wall bounce back with different velocities according to the 
"bounciness" or elasticity of the ball.  We will examine the cases in which 
collision problems are soluble, and make some general statements about 
collisions.
Elastic Collisions
A special category of collisions is called elastic collisions.
Formally, 
an elastic condition is one in which kinetic energy is conserved.  This may be 
difficult to grasp conceptually, so consider the following test: drop a ball 
from a certain height.  If it hits the floor and returns to its original height, 
the collision between the ball and the floor is elastic.  Otherwise it is 
inelastic.  Collisions between pool balls are generally elastic; car crashes are 
generally inelastic. 
Why are these collisions special?  We know with all collisions that 
momentum is conserved.  If two particles collide we can use the following 
equation:
| m1v1o + m2v2o = m1v1f + m2v2f |  | 
 
However, we also know that, because the collision is elastic, kinetic energy is 
conserved. For the same situation we can use the following equation:
|  m1v1o2 +  m2v2o2 =  m1v1f2 +  m2v2f2 |  | 
 
Again, we are usually given the masses and the initial velocities of the two 
colliding particles, so we are given 
m1,
m2,
v1o and 
v2o.  If we 
use these equations together, we now have two 
equations and two unknowns: 
v1f and 
v2f.  Such a situation is always 
soluble, and we can always find the final velocities of two particles in an 
elastic collision.  This is a powerful use of both conservation laws we have 
seen so far--the two work wonderfully to predict the outcome of elastic 
collisions.
Inelastic Collisions
So what if energy is not conserved?  Our knowledge of such situations is more 
limited, since we no longer know what the kinetic energy is after the collision.  
However, even though kinetic energy is not conserved, momentum will always be 
conserved.  This allows us to make some statements about inelastic 
collisions.  Specifically, if we are given the masses of the particles, both 
initial velocities and one final velocity we can calculate the final velocity of 
the last particle through the familiar equation:
| m1v1o + m2v2o = m1v1f + m2v2f |  | 
 
Thus we have at least a little knowledge of inelastic collisions.