Collisions

Since the theory behind solving two dimensional collisions problems is the same as the one dimensional case, we will simply take a general example of a two dimensional collision, and show how to solve it. Consider two particles, m₁ and m₂, moving toward each other with velocity v1o and v_2o, respectively. They hit in an elastic collision at an angle, and both particles travel off at an angle to their original displacement, as shown below: To solve this problem we again use our conservation laws to come up with equations that we hope to be able to solve. In terms of kinetic energy, since energy is a scalar quantity, we need not take direction into account, and may simply state:

Whereas in the one dimensional problem we could only generate one equation for the conservation of linear momentum, in two dimensional problems we can generate two equations: one for the x-component and one for the y-component.

Let's start with the x-component. Our initial momentum in the x direction is given by: m₁v1o - m₂v_2o. Note the minus sign, as the two particles are moving in opposite directions. After the collision, each particle maintains a component of their velocity in the x direction, which can be calculated using trigonometry. Thus our equation for the conservation of linear momentum in the x-direction is:

Regarding the y-component, since both particles move initially in the x direction, there is no initial linear momentum in the y direction. The final linear momentum again can be found through trigonometry, and used to form another equation:

We now have three equations: conservation of kinetic energy, and conservation of momentum in both the x and y directions. With this information, is this problem solvable? Recall that if we are given only the initial masses and velocities we are working with four unknowns: v_1f, v_2f, θ₁ and θ₂. We cannot solve for four unknowns with three equations, and must specify an additional variable. Perhaps we are trying to make a pool shot, and can tell the angle of the ball being hit by where the hole is, but would like to know where the cue ball will end up. This equation would be solvable, since with the angle the ball will take to hit the pocket we have specified another variable.

Surprisingly enough, the completely inelastic case is easier to solve in two dimensions than the completely elastic one. To see why, we shall examine a general example of a completely inelastic collision. As we've done previously, we will count equations and variables and show that it is solvable.

The most general case of a completely inelastic collision is two particles m₁ and m₂ moving at an angle of θ₁ to each other with velocities v₁ and v₂, respectively. They undergo a completely inelastic collision, and form a single mass M with velocity v_f, as shown below. What equations can we come up with to solve this type of problem? Clearly because the collision is inelastic we cannot invoke the conservation of energy. Instead we are limited to our two equations for conservation of linear momentum. Observe that we have conveniently oriented our axes in the figure above such that the path of m₁ is entirely in the x direction. With this in mind, we can generate our equations for the conservation of momentum in both the x and y directions:

Though we only have two equations, we also only have two unknowns, v_f andθ₂. Thus we can solve for any completely inelastic collision in two dimensions.

Our entire study of collision can be seen as simply an application of the conservation of linear momentum. So much time is spent on this topic, however, because it is such a common one, both in physics and in practical life. Collisions occur in particle physics, pool halls, car accidents, sports, and just about anything else you can think of. A thorough study of the topic will be well rewarded in practical use.