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No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
Mastery Quizzes
Infographics
Graphic Novels
AP® Test Prep PLUS
AP® Practice & Lessons
My PLUS Activity
Note-taking
Bookmarking
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Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with
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Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
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Note that the exponents are not a and b but some experimentally determined
powers p and q which
may or may not equal a and b. The order of the
is, therefore, p + q.
We will discuss in Determining Rate Laws how those
exponents can be
determined.
Also notice in the the presence of
the rate constant
k. Students often have trouble distinguishing between the rate of a
reaction and its rate constant. The
rate of a reaction is the total rate of a reaction and is the "rate" in the
rate law. The units of rate are
always M / s. The rate constant, k, is an experimentally determined
proportionality constant that
gives some measure of the intrinsic "reactivity" of the reaction. The
units on the rate constant depend
on the order of the reaction, n, such that k has units M1 - n /
s. In that way, the units
of the rate constant, k, are chosen to make the units of rate always M / s
regardless of order. For
example, if the order of the reaction is 3, the rate law could be rate = k
[A]2[B]. The
units of rate are M / s and the rate constant must, therefore, have units
of M-2 / s.
The attentive reader may have noticed that we have only considered the rate
of the forward reaction,
neglecting any sort of reverse reaction in the rate law. To make our math
easier, we have
intentionally ignored the reverse reaction and we will continue to do so.
This is a justified practice
for reactions with negligible reverse rates, such as those with equilibrium
constants, K, much greater
than 1. For reactions with K's around 1, this is also a valid
approximation because they are usually
carried out such that products are removed from the reaction mixture as
they are formed, keeping
concentrations of products low.
Rate laws can also be expressed to relate the concentration of reactants to
the time of the reaction.
Such an expression is called an integrated rate law because it is the
integral of the differential rate
law. For those of you who have had some calculus, we present a derivation of an
integrated rate
law from the differential rate law below for a first order
reaction. If you have
not had calculus, don't worry. Just pay attention to the end result of the
derivation.
Rearranging this equation gives the following:
Using a similar technique, one can derive the integrated rate law for any
differential rate law. As we
will see in Determining Rate Laws, the fact that the
1st order integrated rate
law is linear allows us to test if a reaction is first order by plotting ln
[A] versus time.