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No Fear Translations of Shakespeare’s plays (along with audio!) and other classic works
Flashcards
Mastery Quizzes
Infographics
Graphic Novels
AP® Test Prep PLUS
AP® Practice & Lessons
My PLUS Activity
Note-taking
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No Fear
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Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with
understanding the crux of the text.
Kay
H.
Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
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Calculate the pressure of a Fermi gas in its ground state.
Remember that p = - .
We recall that Ugs = N. Now we need only to
calculate the derviative. Don't forget that is a function
of the volume. The simplified result is:
p = n
Problem :
Check that the energy of the ground state of a Fermi gas is correct by
calculating the chemical potential from it.
Recall that μ = .
We take the appropriate derivative, remembering that is a
function of N, and find that μ = . This shouldn't surprise
us; we defined the Fermi energy to be exactly the chemical potential at a
temperature of zero, which is the approximate requirement for the ground
state to be occupied.
Problem :
A long series of calculations can be used to derive the entropy of the
Fermi gas, and the result is σ = Π2N. From this, calculate the heat capacity at constant
volume.
Remember that CV = τ.
The algebra is simple, and yields CV = Π2N.
Problem :
It turns out that the energy of a Bose gas is given by: U = Aτ where A is a constant that depends only on the volume. From this,
calculate the heat capacity at constant volume.
Using the equation CV = ,
which comes from the more primitive definition of the heat capacity via the
thermodynamic identity, we find CV = .
Problem :
Using the knowledge that the entropy goes to zero as the temperature
goes to zero, calculate the entropy from the heat capacity.
Remember that CV = τ. We
solve for σ, performing the integration from 0 to τ, and
setting the arbitrary constant equal to 0 in order that the conditions
at τ = 0 are met, and get: σ = .