Problem :
| 4NH3(g) + 6NO(g)→5N2(g) + 6H2O(g) |
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How many moles of each reactant were there if 13.7 moles of
N2(g) is produced?
×4 moles NH3(g) = 10.96 moles NH3(g) | | |
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×6 moles NO(g) = 16.44 moles NO(g) | | |
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So we have 10.96 moles
NH3(g) and 16.44 moles NO(g).
Problem :
What is the mass of 2 moles of H2S?
GFM of H = 1
GFM of S = 32>br>
GFM of H2S = 2×1 + 32 = 34 grams / mole
×34 grams = 68 grams | | |
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Problem : 2Al +3Cl2→2AlCl3
When 80 grams of aluminum is reacted with excess chlorine gas, how many
formula units of AlCl3 are produced?
×1 mole Al = 2.96 moles Al | | |
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There is a 1:1 ratio between Al and
AlCl3, therefore there are 2.96
moles
AlCl3.
= 1.78×1025 | | |
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Problem : Sb2S3(s) + 3Fe(s)→2Sb(s) +3FeS(s)
If 3.87×1023 particles of
Sb2S3(s) are
reacted with excess Fe(s), what mass of FeS(s) is produced?
×1 mole Sb2S3(s) = 0.643 moles Sb2S3(s) | | |
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×3 moles FeS(s) = 1.93 moles FeS(s) | | |
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×88 grams = 170 grams | | |
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Problem : CO(g) +2H2(g)→CH3OH(g)
At STP, what volume of H2(g) is needed to react completely
with 8.02×1023 molecules of CO(g)?
×1 mole CO(g) = 1.33 moles CO(g) | | |
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×2 moles H2(g) = 2.66 moles H2(g) | | |
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×22.4 L = 59.7 L | | |
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