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Recall that a number line is a
horizontal line that has points which correspond to numbers. The
points are spaced according to the value of the number they correspond
to; in a number line containing only whole numbers or integers, the
points are equally spaced.

We can graph real numbers by representing them as points on the number
line. For example, we can graph "2" on the number
line:

We can also graph inequalities on the number line. The following graph
represents the inequality x≤2. The dark line
represents all the numbers that satisfy x≤2. If we
pick any number on the dark line and plug it in for x, the inequality
will be true.

The following graph represents the inequality x < 2. Note
that the open circle on 2 shows that 2 is not a
solution to x < 2.

Here are the graphs of x > 2 and x≥2,
respectively:

An inequality with a "≠" sign has a solution set which is all the
real numbers except a single point (or a number of single points).
Thus, to graph an inequality with a "≠" sign, graph the entire
line with one point removed. For example, the graph of x≠2 looks like:

Using the Number Line to Solve Inequalities

We can use the number line to solve inequalities containing <, ≤,
>, and ≥. To solve an inequality using the number line, change
the inequality sign to an equal sign, and solve the equation. Then
graph the point on the number line (graph it as an open circle if the
original inequality was "<" or ">"). The number line should now be
divided into 2 regions -- one to the left of the point and one to the
right of the point

Next, pick a point in each region and "test" it -- see if it satisfies
the inequality when plugged in for the variable. If it satisfies the
inequality, draw a dark line from the point into that region, with an
arrow at the end. This is the solution set to the equation: if one point in the region satisfies the inequality, the entire region will satisfy the inequality.

Example: -3(x - 2)≤12

Solve -3(x - 2) = 12:

x - 2 = - 4 x = - 2

Graph x = - 2, using a filled circle because the original
inequality was ≤:
Plug values into the equation -3(x - 2)≤12:

Pick a point on the left of -2 (-3, for example): -3(- 3 - 2)≤12 ? 15≤12 ? No.
Pick a point on the right of -2 (0, for example): -3(0 - 2)≤12 ? 6≤12 ? Yes.

Draw a dark line from -2 extending to the right, with an arrow at the
end: