Example 2: Find the inverse of f (x) =
, x≥2 (we
must restrict the domain because f (x) is undefined for x < 2).
Original function:
- Subract 2.
- Take the square root.
New function:
- Square.
- Add 2.
Thus,
f-1(x) = x2 + 2.
Check:
f-1(f (x)) = f-1(
) = (
)2 + 2 = (x - 2) + 2 = x.
f (f-1(x)) = f (x2 +2) =
=
= x.
When we take the inverse of a function, the domain and range switch. In example
2, the domain of f is x≥2 and the range of f is f (x)≥ 0. Thus,
the domain of f-1 is x≥ 0 and the range of f-1 is f-1(x)≥2.