Thermodynamics: Gas

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Problems 2

Summary Problems 2

Problem :

Calculate the pressure of a Fermi gas in its ground state.

Remember that p = - . We recall that Ugs = N. Now we need only to calculate the derviative. Don't forget that is a function of the volume. The simplified result is:

p = n

Problem :

Check that the energy of the ground state of a Fermi gas is correct by calculating the chemical potential from it.

Recall that μ = . We take the appropriate derivative, remembering that is a function of N, and find that μ = . This shouldn't surprise us; we defined the Fermi energy to be exactly the chemical potential at a temperature of zero, which is the approximate requirement for the ground state to be occupied.

Problem :

A long series of calculations can be used to derive the entropy of the Fermi gas, and the result is σ = Π2N. From this, calculate the heat capacity at constant volume.

Remember that CV = τ. The algebra is simple, and yields CV = Π2N.

Problem :

It turns out that the energy of a Bose gas is given by: U = where A is a constant that depends only on the volume. From this, calculate the heat capacity at constant volume.

Using the equation CV = , which comes from the more primitive definition of the heat capacity via the thermodynamic identity, we find CV = .

Problem :

Using the knowledge that the entropy goes to zero as the temperature goes to zero, calculate the entropy from the heat capacity.

Remember that CV = τ. We solve for σ, performing the integration from 0 to τ, and setting the arbitrary constant equal to 0 in order that the conditions at τ = 0 are met, and get: σ = .