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Problems 2
Problem :
Calculate the pressure of a Fermi gas in its ground state.
Remember that p = - 

.
We recall that Ugs =
N
. Now we need only to
calculate the derviative. Don't forget that
is a function
of the volume. The simplified result is:
n
Problem :
Check that the energy of the ground state of a Fermi gas is correct by calculating the chemical potential from it.
Recall that μ = 

.
We take the appropriate derivative, remembering that
is a
function of N, and find that μ =
. This shouldn't surprise
us; we defined the Fermi energy to be exactly the chemical potential at a
temperature of zero, which is the approximate requirement for the ground
state to be occupied.
Problem :
A long series of calculations can be used to derive the entropy of the
Fermi gas, and the result is σ =
Π2N

. From this, calculate the heat capacity at constant
volume.
Remember that CV = τ

.
The algebra is simple, and yields CV =
Π2N

.
Problem :
It turns out that the energy of a Bose gas is given by: U = Aτ
where A is a constant that depends only on the volume. From this,
calculate the heat capacity at constant volume.
Using the equation CV = 

,
which comes from the more primitive definition of the heat capacity via the
thermodynamic identity, we find CV = 
.
Problem :
Using the knowledge that the entropy goes to zero as the temperature goes to zero, calculate the entropy from the heat capacity.
Remember that CV = τ

. We
solve for σ, performing the integration from 0 to τ, and
setting the arbitrary constant equal to 0 in order that the conditions
at τ = 0 are met, and get: σ = 
.
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