Problem : If the percent yield of the following equation is 55%, how many moles of H2SO4 are produced when 44.8 L of SO3 are combined with excess water?
|SO3(g) + H2O(l)→H2SO4(aq)|
The equation is balanced, so convert to moles.
|= 2 moles SO3(g)|
Now calculate the theoretical yield. How many moles of H2SO4(aq) should we get?
|= 2 moles H2SO4(aq)|
Now solve algebraically for the actual yield.
|55% = 0.55 = Actual Yield/(2 moles H2SO4(aq))|
|2 moles H2SO4(aq)×0.55 = 1.1 moles H2SO4(aq)|