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Testimonials from SparkNotes Customers
No Fear provides access to Shakespeare for students who normally couldn’t (or wouldn’t) read his plays. It’s also a very useful tool when trying to explain Shakespeare’s wordplay!
Erika M.
I tutor high school students in a variety of subjects. Having access to the literature translations helps me to stay informed about the various assignments. Your summaries and translations are invaluable.
Kathy B.
Teaching Shakespeare to today's generation can be challenging. No Fear helps a ton with understanding the crux of the text.
Kay H.
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Graphing Quadratic Functions
A quadratic function is a function of the form y = ax2 + bx + c, where a≠ 0, and a, b, and c are real numbers.
The y-intercept is given by x = 0: y = a(02) + b(0) + c = c. Thus, the y-intercept is (0, c).
The x-intercept is given by y = 0: 0 = ax2 + bx + c. Thus, the x-intercept(s) can be found by factoring or by using the quadratic formula.
In addition, the discriminant gives the number of x-intercepts of a quadratic function, because it gives us the number of solutions to ax2 + bx + c = 0. If b2 -4ac > 0, there are 2 solutions to ax2 + bx + c = 0 and consequently 2 x-intercepts. If b2 - 4ac = 0, there is 1 solution to ax2 + bx + c = 0, and consequently 1 x-intercept. If b2 -4ac < 0, there are no solutions to ax2 + bx + c = 0, and consequently no x-intercepts. The graph of the function does not cross the x-axis; either the vertex of the parabola is above the x-axis and the parabola opens upward, or the vertex is below the x-axis and the parabola opens downward.
A quadratic function in the form y = ax2 + bx + c is not always simple to graph. We do not know the vertex or the axis of symmetry simply by looking at the equation. To make the function easier to graph, we need to convert it to the form y = a(x - h)2 + k. We do this by completing the square: adding and subtracting a constant to create a perfect square trinomial within our equation.
A perfect square trinomial is of the form x2 +2dx + d2. In order to "create" a perfect square trinomial within our equation, we must find d. To find d, divide b by 2a. Then square d and multiply by a, and add and subtract ad2 to the equation (we must add and subtract in order to maintain the original equation). We now have an equation of the form y = ax2 +2adx + ad2 - ad2 + c. Factor ax2 +2adx + ad2 into a(x + d )2, and simplify - ad2 + c.
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