Hey all, I was hoping someone would be able to point me at a good ordinary differential equations text. Basically right now I have been working out of 'ordinary differential equations" by boyce and brannon. but Im fed up with the book and really would just like a good book to be used as a...
Thanks for looking it over. Your right that is a much easier method.
But in the second part of the question it states "show that when \gamma \geq 1 then the source must have an infinite lifetime.
The way I took this is that if it is to have an infinite life then the \lim _{t...
Im sorry, I posted this in the wrong section, feel free to move it to the homework section.
Hey guys, Ive really been needing some help with this one. Im doing an assignment for Ordinary Differential Equations and I was hoping someone could help me out by looking over my work. Ive been...
Right, and you know that mu_s and mu_k are related by the equation F(friction)=mu*(F(normal))
and because this is a frictionless, massless pulley we are able to relate the tensions of the two boxes.
Arent there a ton of places where you can pay one flat fee to download unlimited music? I think they only charge if you put it on a portable device, I cant remember the exact details though.
Im not entirely sure, how do you find that out?
Heres what I tried anyway. I opened the player then clicked on a song and clicked properties. Then clicked details and it said bit rate was about 3200kbps for most of the songs I checked. But that number seems really high to me.
You should check out the sandisk sansa. I have a 4gb version and I'm happy with it. Its basically an Ipod mini for alot less money and it has alot of features like a voice recorder and radio. Ive used the recorder a couple of times in class and its pretty sensitive. You need to sit at the...
You should probably call their tech support because it sounds like something might not be working properly. Do you know if all the internal fans are running?
Hmm, well Im not really sure how you could change the temperature on a laptop. Are you using it on a soft material i.e. covering the exhaust vents like if it is being used on a bed?
Well firstly stop using that computer because at those temperatures you will wear out the motherboard or cpu really fast.
In order to help you though we will need more information about your system. What cpu do you have and what model motherboard. Also list any other components in the case.
That makes sense if the initial movement is vertical. But how could I find the tension if the initial movement is horizontal. Would'nt that bring us back to the 3 variable 2 equation thing?
If it would help I could scan the problem from the book also.
The problem Im having is that in all the figures (in the image) I have 3 variables with only 2 equations. In figure 3 The only way I could solve for the variables would be to set the normal force equal to the weight, however if the tension is also pulling up it would decrease the normal force...
The sum is the addition of the i, j, and k components of the vector. To find the magnitude of the sum you first need to add the components then find the magnitude of the resultant vector. i.e. take the square root of the sum of the squares.
I actually got to use one the other day at the i store. I didnt care for it, but it was at least an interesting thing. The touchscreen is actually alot better then I had expected but I still had some trouble with hitting multiple letters on the keyboard.(I dont think it would be possible to...
Unless Im missing something I thought the half angle formula was
\tan \frac{\theta}{2} = \frac{\sqrt {1-\cos \theta}}{\sqrt{ 1 + \cos \theta}}
Thats not the same as \tan \frac{\theta}{2} = \frac{\sin \theta}{1 + \cos \theta} right? Or am I making a mistake?
Almost, but not quite. It looks pretty tough to put it in that particular form. The way I mentioned works so I guess Ill just stick with that, especially since remembering all those identities is a pain.
Thanks for the suggestions though.
I think I found it. It came to me when I went to get the mail. :)
basically I have this
tan(30)=\frac {\sqrt {1 - \cos^{2} \theta}}{1+\cos(\theta)}
From here I just put it in a quadratic form and solved.
tan(30)=(sin(theta))/(1+cos(theta))
The only way I can solve this is by using the graph on the calculator. There must be a way to solve it by hand though but I cant find it. Maybe Im just not thinking straight but its really getting to me.